先化简,再求值：5abc-{2a^2*b-[3abc-(4ab^2-a^2*b)]},其中a是最小的正整数,b是绝对值最

a是最小的正整数,所以a=1,b是绝对值最小的负整数所以b=-1
|c|=1/8,所以c=1/8或-1/8..因为abc＞0,所以c=-1/8
5abc-{2a^2*b-[3abc-(4ab^2-a^2*b)]}
= 5abc-[2a^2*b-(3abc-4ab^2+a^2*b)]
= 5abc-(2a^2*b-3abc+4ab^2-a^2*b)
=5abc-2a^2*b+3abc-4ab^2+a^2*b
=5abc+3abc-2a^2*b+a^2*b-4ab^2
=8abc-a^2*b-4ab^2
=8*(1/8)-(-1)-4*1
=1+1-4
= -2