C14 is often used to tell the age of formerly living things.

问题描述:

C14 is often used to tell the age of formerly living things.C14 has a half-life of about 6000 years.Now,a cave is discovered with the remains of burned wood from a fire.The wood was found to be approximately 42000 years old.What percent of the original radioactive C14 remains in the charred wood?
谷歌翻译出来:C14经常被用来告诉岁以前生活的东西.C14的半衰期约6000年.现在,一个山洞里发现的遗骸从火中烧木头的.这种木材被发现是约42000年大的.多少百分比保持在原来的放射性C14烧焦的木头?
1个回答 分类:英语 2014-10-22

问题解答:

我来补答
  m=M(1/2)^(t/T)
  其中M为反应前原子核质量,m为反应后原子核质量,t为反应时间,T为半衰期.
t/T=7
带入m/M=0.78125%
 
 
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