解方程组xy/(x+y)=6/5① yz/(x+z)=12/7 ② xz/(x+z)=4/3,

问题描述:

解方程组xy/(x+y)=6/5① yz/(x+z)=12/7 ② xz/(x+z)=4/3,
1个回答 分类:数学 2014-11-15

问题解答:

我来补答
xy/(x+y)=6/5① ---->(x+y)/(xy)=5/6 1/x+1/y =5/6 (4)
yz/(y+z)=12/7 ② 1/y+1/z= 7/12 (5)
xz/(x+z)=4/3 1/x +1/z=3/4 (6)
(4)+(5)+(6)得
1/x+1/y+1/z=13/12 (7)
(7)-(5)得 x=2
(7)-(6) 得 y=3
(7)-(4)得 z=4
 
 
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