问题描述: 解不等式:7x^2+13x-2/(x+1)(x-2)>=0 1个回答 分类:数学 2014-10-08 问题解答: 我来补答 (7x^2+13x-2)/(x+1)(x-2)>=0(7x-1)(x+2)/(x+1)(x-2)>=0(x+1)(x-2)≠0,x≠-1,x≠2原不等式等则于:(7x-1)(x+2)(x+1)(x-2)>=0且x≠-1,x≠2零点为:x=-2,-1,1/7,2可得原不等式的解为:x 展开全文阅读