问题描述:
∫x/[(1-x)^3]dx
设1-x=u
=∫1/u^(3)dx
=1/3∫1/u^(3)du^3
=1/3In|u^3|+c
=1/3In|(1-x)^3|+c
但貌似是错的,
设1-x=u
=∫1/u^(3)dx
=1/3∫1/u^(3)du^3
=1/3In|u^3|+c
=1/3In|(1-x)^3|+c
但貌似是错的,
问题解答:
我来补答展开全文阅读