问题描述: 已知x+y=[负4],xy=[负12],求分式[y+1/x+1]+[x+1/y+1]的值 1个回答 分类:数学 2014-11-12 问题解答: 我来补答 [y+1/x+1]+[x+1/y+1]=(y+1)^2/(x+1)(y+1)+(x+1)^2/(x+1)(y+1)=[(Y+1)^2+(x+1)^2]/(x+1)(y+1)=[y^2+2y+1+x^2+2x+1]/[xy+x+y+i]=[(y+x)^2-2xy+2x+2y+2]/[-12-4+1]=[(-4)^2-2(-12)+2(-4)+2]/(-15)=-510 展开全文阅读