问题描述: [sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)] 1个回答 分类:综合 2014-10-01 问题解答: 我来补答 sin(A-派)=-sin Acos(A-派)=-cos Acot A=cos A/sin Atan A=sin A/cos A所以[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]=-sin Acot A/(-cos Atan A)=-cos A/(-sin A)=cot A 展开全文阅读