[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]

问题描述:

[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]
1个回答 分类:综合 2014-10-01

问题解答:

我来补答
sin(A-派)=-sin A
cos(A-派)=-cos A
cot A=cos A/sin A
tan A=sin A/cos A
所以[sin(A-派)cot(A-2派)]/[cos(A-派)tan(A-2派)]
=-sin Acot A/(-cos Atan A)
=-cos A/(-sin A)
=cot A
 
 
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