问题描述: 已知tanx+tany=5m,tan(x+y)=6m(m≠0),tan(x-y)=1/7,求m的值及tanx,tany的值 1个回答 分类:数学 2014-11-17 问题解答: 我来补答 tan(x+y)=(tanx+tany)/(1-tanxtany)=6mtanx+tany=5m代入上式tanxtany=1/6tan(x-y)=(tanx-tany)/(1+tanxtany)=1/7tanx-tany=1/6tanx=1/2,tany=1/3,或tanx=-1/3,tany=-1/2tanx=1/2,tany=1/3时,m=1/6tanx=-1/3,tany=-1/2时m=-1/6 展开全文阅读