已知函数f(x)=2sinxcosx+2根号3cos²x-根号3.求f（x）的最小正周期和递增区间.

f(x)=2sinxcosx+2√3cos²x-√3
=2sinxcosx+√3(2cos²x-1)
=sin2x+√3cos2x
=2sin(2x+π/3)
最小正周期T=2π/2=π
-π/2+2kπ