问题描述: 计算[(2+2i)/(根号3-i)]^7-[(2-2i)/(1+根号3i)^7 1个回答 分类:数学 2014-10-01 问题解答: 我来补答 [(2+2i)/(√3-i)]^7=[(1+i)(√3+i)/2]^7=(√2)^7*[(√2/2+√2/2i)(√3/2+1/2i)]^7=(√2)^7*[(cosπ/4+isinπ/4)(cosπ/6+isinπ/6)]^7=(√2)^7*(cos5π/12+isin5π/12)^7=(√2)^7*(cos35π/12+isin35π/12)=(√2)^7*(-cosπ/12+isinπ/12)同理[(2-2i)/(1+√3i)^7=(√2)^7*(cosπ/12-isinπ/12)[(2+2i)/(√3-i)]^7-[(2-2i)/(1+√3i)^7=(√2)^7*(-2cosπ/12+2isinπ/12)cosπ/12,sinπ/12 自己用半角公式算.OK. 展开全文阅读