x^-2√3 x=0, 4x^-121=0, (x-4)^=(5-2x)^ 用因式分解法解方程

x^2-2√3 x=0
x(x-2√3)=0
x=0,x=2√3
4x^2-121=0
(2x)^2-11^2=0
(2x+11)(2x-11)=0
x=-11/2,x=11/2
(x-4)^2=(5-2x)^2
(x-4)^2-(5-2x)^2 =0
(x-4+5-2x)(x-4-5+2x)=0
(-x+1)(3x-9)=0
-3(x-1)(x-3)=0
x=1,x=3