计算x²-5xy²+6分之x²-3x+2的平方/x²-2x-3分之x-1的平方

请核对题目是不是多写了y²
x²-5x+6分之x²-3x+2的平方/x²-2x-3分之x-1的平方
=[(x²-3x+2)/(x²-5x+6)]²/[(x-1)/(x²-2x-3)]²
=[(x-1)(x-2)/(x-2)(x-3)]²/[(x-1)/(x-3)(x+1)]²
=[(x-1)/(x-3)]²/[(x-1)/(x-3)(x+1)]²
=(x-1)²/(x-3)²*(x-3)²(x+1)²/(x-1)²
=(x+1)²
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