如图所示,在四边形ABCD中,∠BAD=∠C=90°且AB=AD,AE垂直BC垂足为E,若AE=2√3,求四边形ABCD

作AM⊥CD于M ∠EBA=180-∠ABC ∠ADM=360-90-90-∠ABC=180-∠ABC
∴∠ABE=∠ADM ∴△ABE≡△ADM ∴AM=AE=2√3
S△ABE=S△ADM ∴S四边形ABCD=S矩形AECM = 2√3 × 2√3=12