问题描述： 计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y 1个回答 分类：数学 2014-09-20 问题解答： 我来补答 计算:a/(a+1)^2+1/(a+1)^2 =(a+1)/(a+1)^2=1/(a+1),2x/x^2-64y^2-1/x-8y=2x/(x^2-64y^2)-(x+8y)/(x-8y)(x+8y)=(2x-x-8y)/(x-8y)(x+8y)=1/(x+8y) 展开全文阅读
