问题描述: 用对数求导法求导:y=[x*(x^2+1)/(x-1)^2]^1/3 1个回答 分类:数学 2014-12-11 问题解答: 我来补答 等式两边取对数有:lny=1/3ln[x*(x^2+1)/(x-1)^2]化简得3lny=lnx+ln(x^2+1)-2ln|x-1|两边求导3y'/y=1/x+2x/(x^2+1)-2/(x-1)y'=1/3*y[1/x+2x/(x^2+1)-2/(x-1)]=1/3*[1/x+2x/(x^2+1)-2/(x-1)]*[x*(x^2+1)/(x-1)^2]^1/3 展开全文阅读