已知x满足不等式log1/2x^2≥log1/2(3x-2),求函数f(x)=(log2^x/4)*(log2^x/2)

log1/2x^2≥log1/2(3x-2),
则x^2≤3x-2,且3x-2>0
得1≤x≤2
f(x)=(log2^x/4)*(log2^x/2)=log2 （x^2/8)
f(x)min=f(1)=-3
f(x)max=f(2)=-1