已知函数f(x)=log2(x/4)*log4(x/2)（2≤x≤4)

1、
x=4^(2/3)
因为2=4^(1/2)
所以f(x)=log2[4^(2/3-1)]*log4[4^(2/3-1/2)]
=log2[2^(-2/3)]*log4[4^(1/6)]
=-2/3*1/6
=-1/9
2、
f(x)=[log2(x)-log2(4)][log4(x)-log4(2)]
=[log2(x)-log2(2^2)][log4(x)-log4(4^1/2)]
=(t-2)(t-1/2)
=t²-5t/2+1
2