问题描述: 函数f(x)=cosx+根号3sinx(0<=x<=π/2)f (x)的最小值是? 1个回答 分类:数学 2014-11-24 问题解答: 我来补答 f(x)=√3sinx+cosx=2(√3/2sinx+1/2cosx)=2sin(x+π/6)0≤x≤π/2π/6≤x≤2π/3sint在π/6≤x≤2π/3[],先增后减,1/2≤sin(x+π/6)≤11≤2sin(x+π/6)≤2f(min)=1 展开全文阅读