问题描述: lim(x→0)(1-cosx)[x-ln(1+tanx)]/(sinx)^4 1个回答 分类:数学 2014-10-24 问题解答: 我来补答 =lim(x→0)x^2/2*[x-ln(1+tanx)]/[x^4]=lim(x→0)[x-ln(1+tanx)]/[2x^2]=lim(x→0)[1-secx^2/(1+tanx)]/(4x)=lim(x→0)(1+tanx-secx^2)/[4(1+tanx)sinx]=lim(x→0)(cosx^2+cosx*sinx-1)/[4(1+tanx)sinxcosx^2]=lim(x→0)(cosx-sinx)/[4(1+tanx)cosx^2]=1/4 展开全文阅读