数学啊高一 

（1）f(x)=1-cos(π/2+2x)-√3cos2x
=1+sin2x-√3cos2x
=1+2sin(2x-π/3)
∴最小正周期T=2π/2=π,
∵递增,2x-π/3∈[2kπ-π/2,2kπ+π/2]
∴递增区间x∈[kπ-π/2,kπ+5π/12]
(2)∵x∈[π/4,π/2]
∴2x-π/3∈[π/6,2π/3]
∴sin(2x-π/3)∈[1/2,1]
∴f(x)∈[2,3]
∵f(x)-m=2
∴f(x)=m+2∈[2,3]
∴m∈[0,1]
再问： 谢谢哈