a@b=n(常数) (a+1)@b=n+1 a@(b+1)=n-2 1@1=2 2008@2008=?(@是一个特殊的运

a+b=n,(a+1)+b=n+1
=>
1+1=2
2008 + 1 = 2009
a+b=n,a+(b+1)=n-2
=>
2008 + 1 = 2009
2008 + 2 = 2007
……
2008 + 2008 = 2009-2*2007 = -2005