如图,菱形ABCD中,对角线AC、BD交于点O,若AB=13cm,AC=24cm,BD=10cm,求菱形ABCD两边之间

∵ABCD是菱形
∴AC⊥BD
∴S菱形ABCD
=1/2OA×BD+1/2OC×BD
=1/2BD×(OA+OC)
=1/2×BD×AC
=1/2×10×24
=120
∴AB、CD两边之间的距离=120÷13=120/13