问题描述： 化简求值：x-y/x²-2xy+y²-xy+y²/x²-y²,其中(x-2)²+y-3的绝对值=0【很急, 1个回答 分类：数学 2014-11-30 问题解答： 我来补答 (x-2)²+∣y-3∣=0(x-2)²=0,∣y-3∣=0x=2y=3(x-y)/(x²-2xy+y²)-(xy+y²)/(x²-y²)=(x-y)/(x-y)²-y(x+y)/(x-y)(x+y)=1/(x-y)-y/(x-y)=(1-y)/(x-y)=(1-3)/(2-3)=-2/(-1)=2 展开全文阅读
