函数y=f(x)是定义域为R的奇函数,当x＞0,f(x)=9^(x-1/2),则f(log1/3 6)=?

f(log1/3 6)=-f(-log1/3 6)=-f(log1/3 1/6)
=-9^((log1/3 1/6-1)/2)
=-9^((log1/3 1/2)/2)
=-3^log3 2
=-2