若(x+y-5)^2+lx-y+3l=0

问题描述:

若(x+y-5)^2+lx-y+3l=0
x^2-y^2=?
1个回答 分类:数学 2014-11-13

问题解答:

我来补答
因为 (x+y-5)^2 >=0, lx-y+3l >=0, (x+y-5)^2+lx-y+3l=0
所以 (x+y-5)^2 =0, lx-y+3l =0
所以 x+y = 5, x-y = -3
所以 x^2-y^2 = (x+y)*(x-y) = -15
 
 
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