已知f(x)=sin²x+2sinxcosx+3cos²x,x∈(0,兀)求；1函数的最小正周期和值

y=1+sin2x+cos²x
=1+sin2x+1+cos2x
=2+sin2x+cos2x
=2+√2sin(2x+π/4)
所以周期为T=2π /2=π
(2) -π/2+2kπ