问题描述:
已知函数f(x)=ex,曲线y=f(x)在点(x0,y0)处的切线方程为y=g(x).
(Ⅰ)证明:对∀x∈R,f(x)≥g(x);
(Ⅱ)当x≥0时,f(x)≥1+
(Ⅰ)证明:对∀x∈R,f(x)≥g(x);
(Ⅱ)当x≥0时,f(x)≥1+
ax |
1+x |
问题解答:
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