(a-1)分之4+(a+2)分之2-(a-2)分之2-(a+1)分之4

问题描述:

(a-1)分之4+(a+2)分之2-(a-2)分之2-(a+1)分之4
1个回答 分类:数学 2014-11-12

问题解答:

我来补答
[(a-2)/a(a+2)-(a-1)/(a+2)^2]除以((a-4)/(a+2)
=(a^2-4-a^2+a)/a(a+2)^2 * (a+2)/(a-4)
=(a-4)/a(a+2)^2 * (a+2)/(a-4)
=1/a(a+2)
(a-1)^2=0
a=1…
 
 
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