求方程（2x-1)(2y+5)=2009的正整数解

（2x-1)(2y+5)=2009=41*7*7=41*49=287*7=2009*1
2x-1=41
2y+5=49,x=21,y=22
2x-1=49
2y+5=41,x=25,y=18
2x-1=287
2y+5=7,x=144,y=1
2x-1=7
2y+5=287,x= 4,y=141
2x-1=1
2y+5=2009,x=1,y=1002