先化简,再求值：x2+2x+1分之x+1除以2-2x分之x2-x,其中x=-根号2

原式=(x+1)/(x+1)² ×x(x-1)/[-2(x-1)]
=-1/(x+1)×x/2
=-x/2(x+1)
当x=√2时
原式=-√2/2(√2+1)
=-√2(√2-1)/2
=(√2-2)/2