y=sin(x+y)的二阶导数怎么做?这是涉及微分方程里的哪些内容?还是涉及什么其他内容,

隐函数求导问题：F(x,y)=y-sin(x+y)=0
F'(x)=-cos(x+y)
F'(y)=1-cos(x+y)
dy/dx=-F'(x)/F'(y)=cos(x+y)/[1-cos(x+y)]
d^2y/dx^2=d/dx{cos(x+y)/[1-cos(x+y)]}
={-(1+y')sin(x+y)-cos(x+y)(1+y')sin(x+y)}/[1-cos(x+y)]^2
=-(1+y')sin(x+y)[1+cos(x+y)]/[1-cos(x+y)]^2
=-{1+cos(x+y)/[1-cos(x+y)]]sin(x+y)[1+cos(x+y)]/[1-cos(x+y)]^2
=-sin(x+y)[1+cos(x+y)]/[1-cos(x+y)]^3
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再答： 对