问题描述: 【数学】高一三角函数证明题求证:tan^2α-sin^2α=tan^α*sin^2α 1个回答 分类:数学 2014-11-15 问题解答: 我来补答 tan^2α-sin^2α=sin^2a/cos^2a-sin^2a=sin^2a(1/cos^2a-1)=sin^2a {(1-cos^2a)/cos^2a}=sin^2a {sin^2a/cos^2a}=sin^2a * tan^2a记住tana=sina/cosa 展开全文阅读