问题描述： 求函数z=e^xy*cos(x+y)的全微分dz 1个回答 分类：数学 2014-11-30 问题解答： 我来补答 我来试试吧...z=e^xy*cos(x+y) Z'x=ye^xycos(x+y)-e^xysin(x+y) Z'y=xe^xycos(x+y)-e^xysin(x+y) 故dZ=[ye^xycos(x+y)-e^xysin(x+y)]dx+[xe^xycos(x+y)-e^xysin(x+y)]dy 展开全文阅读
