计算,要有过程25x²-16y²=25x²+20xy+4y²=x³-2

问题描述:

计算,要有过程
25x²-16y²=
25x²+20xy+4y²=
x³-25x=
3x²+6xy+3y²=
(x-y)²+4xy=
(a+b)²+2(a+b)+1=
(x²+y²)²-4x²y²=
ab+a+b+1=
(x-1)(x-2)-2(2-x)²=
(a²+ab+b²)²-9a²b²=
1个回答 分类:数学 2014-10-14

问题解答:

我来补答
25x²-16y²
=(5x)²-(4y)²
=(5x+4y)(5x-4y)
25x²+20xy+4y²
=(5x)²+2×5x×2y+(2y)²
=(5x+2y)²
x³-25x
=x(x²-5²)
=x(x+5)(x-5)
3x²+6xy+3y²
=3(x²+2xy+y²)
=3(x+y)²
(x-y)²+4xy
=x²-2xy+y²+4xy
=x²+2xy+y²
=(x+y)²
(a+b)²+2(a+b)+1
=[(a+b)+1]²
=(a+b+1)²
(x²+y²)²-4x²y²
=(x²+y²+2xy)(x²+y²-2xy)
=(x+y)²(x-y)²
ab+a+b+1
=a(b+1)+(b+1)
=(b+1)(a+1)
(x-1)(x-2)-2(2-x)²
=(x-1)(x-2)-2(x-2)²
=(x-2)(x-1-2x+4)
=(x-2)(3-x)
(a²+ab+b²)²-9a²b²
=(a²+ab+b²+3ab)(a²+ab+b²-3ab)
=(a²+4ab+b²)(a²-2ab+b²)
=(a²+4ab+b²)(a-b)²
 
 
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