问题描述: cos(y^2-x^2)求导u(x,y)=e^2xycos(y^2-x^2) 1个回答 分类:数学 2014-11-09 问题解答: 我来补答 ux=2ye^2xycos(y^2-x^2)+e^2xysin(y^2-x^2) *(-2x)=2ye^2xycos(y^2-x^2)-2xe^2xysin(y^2-x^2) uy=2xe^2xycos(y^2-x^2)+e^2xysin(y^2-x^2) *(2y)=2xe^2xycos(y^2-x^2)+2ye^2xysin(y^2-x^2) 展开全文阅读