已知关于x的方程2x(kx-4)-x²+6=0有实根（1）求K的最大整数解

2x(kx-4)-x²+6=0
1)
(2k-1)x^2-8x+6=0
判别8^2-4*6*(2k-1)>=0
k0
(根号β/α+根号α/β)^2
=[(x1+x2)^2-2x1x2]/(x1x2)+2
=(x1+x2)^2/(x1x2)
=64/6
根号β/α+根号α/β=4√6/3