解方程b/a+x=a/x-b+2(a、b为常数且a不等于b

原方程= b(X-b)=a(a+X)+2(X-b)(X+a),Xb-b²=aX+a²+2X²-2bX+2aX-2ab,
2X²+(a-b)²+3aX-3bX=0,2X²+3X(a-b)+(a-b)²=0,
( 2X+a-b)(X+a-b)=0,X1=b-a,X2=(b-a)/2