已知f（x）是一次函数,且满足3f(x+1)-2f(f-1)=2x+17,求f(x).

设f(x) = kx + b
因为3f(x + 1) - 2f(x - 1) = 2x + 17
所以 3(kx + k + b) - 2(kx - k + b) = 2x + 17
kx + 5k + b = 2x + 17
所以 k = 2 ,5k + b = 17
所以 b = 7
所以f(x) = 2x + 7