ln(x+sqr(1+x2))求导怎么求

问题描述:

ln(x+sqr(1+x2))求导怎么求
1个回答 分类:综合 2014-11-13

问题解答:

我来补答
=1/[x+√(1+x²)] × [x+√(1+x²)]'
=1/[x+√(1+x²)] × [1+√(1+x²)']
=1/[x+√(1+x²)] × [1+1/2√(1+x²) ×(1+x²)']
=1/[x+√(1+x²)] × [1+x/√(1+x²)]
=1/√(1+x²)
 
 
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