计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)

问题描述：

计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
1个回答 分类：数学 2014-10-21

问题解答：

我来补答
[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
=[(x+2)(x-2)/(x-3)(x+2)+(x+2)/(x-3)] /(x+1)/(x-3)
=[(x-2)/(x-3)+(x+2)/(x-3)] /(x+1)/(x-3)
=2x/(x-3)/(x+1)/(x-3)
=2x/(x+1)
 
 
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