已知f(x)=x[1\(-n^2+2n+3)](n属于Z）的图像在[0,正无穷）上单调递增,解不等式f(x^2-x)>f

已知f(x)=x[1\(-n^2+2n+3)](n属于Z）的图像在[0,正无穷）上单调递增
1\(-n^2+2n+3)>0
f(x^2-x)>f(x+3)
(x^2-x)[1\(-n^2+2n+3)]>(x+3)[1\(-n^2+2n+3)]
x^2-x>x+3
x^2-2x-3>0
(x-3)(x+1)>0
解得x3