两颗人造地球卫星都沿圆轨道绕地球运行,它们运行轨道半径之比R1:R2=1:2,它们的质量之比m1:m2=1:2,则

GMm/r² = mv²/R → v = √GM/R → v∝√1/R → v1∶v2 = √R2/R1 = √2 ∶1
GMm/R² = mω²R → ω = √GM/R³ → ω∝√1/R³ → ω1∶ω2 = √(R2/R1)³ = 2√2 ∶1
GMm/R² = m· 4π²/T ·R → T=√4π²R³/GM →T∝√R³ →T1∶T2 =√R1³/R2³ = 1∶2√2
F = GMm/R² → F∝m/R² → F1∶F2 = (m1/m2)(R2/R1)² = 2 ∶1
若不明白,