若m-n=4,mn=-1,求代数式(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值

问题描述:

若m-n=4,mn=-1,求代数式(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
1个回答 分类:数学 2014-12-12

问题解答:

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(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=9-2mn+2m+3n- 3mn-2n+2m-m-4n-mn
=9-6mn+3m-3n
=9-6mn+3(m-n)
=9-6×(-1)+3×4
=9+6+12
=27
 
 
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