问题描述: x+3分之1减3减x分之2=x的2次方减9分之12 1个回答 分类:数学 2014-12-08 问题解答: 我来补答 1/(x+3)-2/(3-x)=12/(x²-9)1/(x+3)+2/(x-3)=12/(x²-9)[(x-3)/((x+3)(x-3)]+[2(x+3)/(x+3)(x-3)]=12/(x²-9)(x-3)/(x²-9)+2(x+3)/(x²-9)=12/(x²-9)[(x-3)+2(x+3)]/(x²-9)=12/(x²-9)x-3+2x+6=123x+3=123x=12-3x=3经检验x=3是原方程的增根所以原方程无解. 展开全文阅读