问题描述： 一道等比数列数学题 1个回答 分类：数学 2014-12-16 问题解答： 我来补答 a5-a1=a1(q^4-1)=a1(q^2+1)(q^2-1)=15````````````1a4-a2=a1q(q^2-1)=6```````````````````````````````````21、2相比得：得：q^2+1=5q/2 即：q=2 或 q=1/2 (舍去)q=2则a1=1a3=a1q^2=4 展开全文阅读
