已知函数f(x)=1/2cosx^2+（根号3）/2*sinxcosx+1

f(x)=√3/4*sin2x+1/4*(1+cos2x)+1
=√3/4*sin2x+1/4*cos2x)+5/4
=(1/2)sin(2x+z)+5/4
tanz=(1/4)/(√3/4)=1/√3
z=π/6
所以f(x)=(1/2)sin(2x+π/6)+5/4
所以T=2π/2=π
f(x)=1
sin(2x+π/6)=-1/2
2x+π/6=2kπ-π/6,2x+π/6=2kπ-5π/6
所以集合={x|x=kπ-π/6,x=kπ-π/2,k属于Z}