问题描述:
y=sin(x-π/3)cosx=[sin(2x-π/3)+sin(-π/3)]/2
为什么y=sin(x-π/3)cosx,就说明y=[sin(2x-π/3)+sin(-π/3)]/2,望会此题者给小妹说一下,
为什么y=sin(x-π/3)cosx,就说明y=[sin(2x-π/3)+sin(-π/3)]/2,望会此题者给小妹说一下,
问题解答:
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