问题描述: 若多项式5x²-2mxy-3y²+4xy-3x+1中不含xy项,求(-m³+2m²-m+1)-(m³+2m²-m 1个回答 分类:数学 2014-12-06 问题解答: 我来补答 5x²-2mxy-3y²+4xy-3x+1=5x²+(4-2m)xy-3y²-3x+1不含xy项所以系数为04-2m=0m=2(-m³+2m²-m+1)-(m³+2m²-m)=-m³+2m²-m+1-m³-2m²+m=-2m³+1=-2×2³+1=-15 展开全文阅读