先化简再求值[(3a-7)^2-(a+5)^2]\(4a-24)其中a=0.02

问题描述:

先化简再求值[(3a-7)^2-(a+5)^2]\(4a-24)其中a=0.02
1个回答 分类:数学 2014-10-27

问题解答:

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[(3a-7)^2-(a+5)^2]\(4a-24)
=[(3a-7+a+5)*(3a-7-a-5)]/(4a-24)
=(4a-2)*(2a-12)/(4a-24)
=(2a-1)(a-6)/(a-6)
=2a-1
=2×0.02-1
=0.04-1
=-0.96
 
 
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