问题描述: 已知x=根号2+1,求代数式x/x-1+(x-2/x²-1)/(x²-2x-2/x²+2x+1)的值要详细的解法 1个回答 分类:综合 2014-10-23 问题解答: 我来补答 x/x-1+(x-2/x²-1)/(x²-2x-2/x²+2x+1)=x/(x-1)+[(x-2)/(x-1)(x+1)]/[(x²-2x-2)(x+1)²]=x/(x-1)+(x-2)(x+1)/[(x-1)(x²-2x-2)]=[x(x²-2x-2)+(x-2)(x+1)]/(x-1)(x²-2x-2)=[(√2+1)(3+2√2-2√2-2-2)+(√2+1-2)(√2+1+1)]/[(√2+1-1)(3+2√2-2√2-2-2)]=[(√2+1)(-1)+(√2-1)(√2+2)]/(-√2)=(-√2+2+√2-2)/(-√2)=0 展开全文阅读